Which of the following statements about the reaction given below are ...
Jan 4, 2023 · Answer: C. (i) and (ii) only Explanation: GIVEN REACTION: MnO2 + 4HCl → MnCl2 + 2H2O + Cl2 Let's break the given reaction into two halves: Oxidation half: HCl is oxidized to Cl2, …
21. State whether the given chemical reaction is a redox ... - Brainly
Aug 15, 2023 · Answer: Yes, the given chemical reaction is a redox reaction. In this reaction, manganese dioxide (MnO2) reacts with hydrochloric acid (HCl) to produce manganese chloride …
MnO2 + x HCl→ MnCl + y H₂O + z Cl In order to balance the above ...
Jan 14, 2024 · Find an answer to your question MnO2 + x HCl→ MnCl + y H₂O + z Cl In order to balance the above chemical equation, the values of x, y and z respectively are: (a)…
Balance the following redox reaction by oxidation number method.
Feb 17, 2023 · In the given reaction, MnO2 undergoes reduction whereas Br^- gets oxidized. The unbalanced equation is: MnO2 + Br^- → Mn2^+ + Br2 + H2O Assigning oxidation states, we get: Mn: …
Mno4+h2o2 =mno2+o2+h2o balance using oxidation number method
Nov 9, 2023 · Find an answer to your question mno4+h2o2 =mno2+o2+h2o balance using oxidation number method
n factor of MnO2 plz with reason!!!! - Brainly.in
Jun 28, 2020 · Here, n = 3 so, equivalent weight = 158/3 = 52.66 gm/equivalent For, MnO2 (molar mass = 87) , here n = 3 So, equivalent weight = molar mass/ 3 = 87/3 = 29 gm/equivalent. i hope it will help …
Assertion : MnO2 + 4 HCl MnCl2 + Cl2 + 2H2O is a redox ... - Brainly
Sep 29, 2020 · The electrons lost in the process of oxidation of one half of the reaction is taken up by the reactant which gets reduced. Hence the number of electrons lost and gained in a balanced redox …
An example of a disproportionation reaction is - Brainly
Feb 14, 2023 · Answer: A: 2 KMnO4 - K2MnO4 + MnO2 + O2. Explanation: In a disproportionation reaction, a single substance is simultaneously oxidized and reduced to form two different products. In …
MnO4- + i- + h2o---> mno2+ oh- + io3- - Brainly.in
Feb 27, 2025 · The given equation is a redox reaction, where permanganate (MnO4-) is reduced to manganese (IV) oxide (MnO2), and iodide (I-) is oxidized to iodate (IO3-). Here's the balanced equation:
How to balance MnO4- (aq) + I- (aq) - MnO2 (s) + I2 (s) in ... - Brainly
Feb 11, 2019 · MnO4^- + I - ----> MnO2 + I2 first let us find oxidation no. of I oxidation state of oxygen is alway -2 except in peroxides n other cases charge on I is -1 so its oxidation no. is -1 hope you …