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  1. Question #1b0ff - Socratic

    First of all, a square root cannot produce a negative number, so we know part of the range is -1<=x. At this point, when calculating it further, we only need the part inside the radical, or 1-x^2. Just by …

  2. Question #4242c - Socratic

    Substitute cos (2x) = 2cos^2 (x)-1 Use the quadratic formula on the resulting equation. Use the inverse cosine function on the two cases. Add the periodic nature of the function.

  3. How do you find the domain and range of g(t) = 5t? | Socratic

    See explanation. Domain The domain is the largest subset of real numbers RR for which the function is defined. To find it we have to look for any possible values of x for which the function is undefined. …

  4. We have f:RR->RR,f (x)=root (3) (x^2+mx+1).Which are values

    We have #f:RR->RR,f (x)=root (3) (x^2+mx+1)#.Which are values of #m# for which the graph of #f# has tangent in every point in #RR#?

  5. 302 Moved

    302 Moved The document has moved here.

  6. Site Map - Recent Questions | Socratic

    After another 6 months of not selling, it is further marked down by 10 %. Find the sale price after both markdowns? What is the general soultion to 2tan^2x + sec^2x = 2 ? How do you solve this function? …

  7. Answers created by Anthony X - Socratic

    How do you find the domain and range of #x^2+y^2=9#? How do you find the axis of symmetry, graph and find the maximum or minimum value of the function #y = –x^2 + 6x – 1#? How do you rationalize …

  8. Anna on Socratic

    Anna gets smarter on Socratic Anna joined Socratic 6.498630136986302 years ago. Anna hasn't written a biography yet. 1 Asked

  9. Aron N. on Socratic

    Aron N. gets smarter on Socratic Aron N. joined Socratic 7.257534246575342 years ago. Aron N. hasn't written a biography yet. 1,475 students helped 1 Answer

  10. Ahmed Mohamed on Socratic

    Ahmed Mohamed gets smarter on Socratic Ahmed Mohamed joined Socratic 7.043835616438356 years ago. Ahmed Mohamed hasn't written a biography yet. 2,428 students helped 1 Answer 1 Asked